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Sum an arbitrarily nested integer list
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Implement nested_total(value) where value is either an integer or a
list containing more valid values. Lists may be empty and nesting depth is
arbitrary. Do not use loops, sum, or slicing.
Reveal answer or reference solution
Use one base case for an integer and a second base case for reaching the end of a list. Recursively total the current child and the remainder by index. Every integer and list position is processed once; stack depth depends on both nesting and list length.
def nested_total(value: int | list) -> int:
if isinstance(value, int):
return value
def total_from(index: int) -> int:
if index == len(value):
return 0
return nested_total(value[index]) + total_from(index + 1)
return total_from(0)Public tests
nested_total(7)→7nested_total([])→0nested_total([1, [2, [], [3]], 4])→10nested_total([[-2], [5, [-1]]])→2nested_total([[[[0]]]])→0
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