Classify values in one pass
Problem
Implement classify_values(xs). Return a dictionary with keys negative, zero, positive_even, and positive_odd. Each value is the count of integers in xs in that category. Use one pass over xs.
Starter code
def classify_values(xs):
passReveal answer or reference solution
def classify_values(xs):
out = {"negative": 0, "zero": 0, "positive_even": 0, "positive_odd": 0}
for x in xs:
if x < 0:
out["negative"] += 1
elif x == 0:
out["zero"] += 1
elif x % 2 == 0:
out["positive_even"] += 1
else:
out["positive_odd"] += 1
return outPublic tests
classify_values([-2, 0, 1, 2, 3, 4])→{'negative': 1, 'zero': 1, 'positive_even': 2, 'positive_odd': 2}classify_values([])→{'negative': 0, 'zero': 0, 'positive_even': 0, 'positive_odd': 0}
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